A 15kW motor running at 380V 50 Hz, 1450RPM is 98.8 N-m (15kW x 9550 / 1450RPM = 98.8 N-m). We already know that if the V/Hz ratio remains constant, torque remains the same. If the voltage is increased to 460V so that torque remains constant when the motor is running 20% faster at 60Hz (1740 RPM), you get 98.8 * 1740/9550 = 18kW.
So you can run VFD from 480 and supply 380. 50 Hz. If you wanted simple, it might be possible to change the motor pulley to 5/6 the present size, and run direct from 480 60Hz. The motor will be OK with that, it's just changing the rpm back to the 50Hz rate.
On both of these grounded. tion (120 or 277 volts) is only available as single-phase. The high-voltage (208 or 480 volts) is available as either single-phase or 3-phase. It should be noted that in the 4-wire ground-ed wye systems the high-voltage is 1.73 times (the square root of 3) higher than the low voltage.
I need to get power to a machine in a weld shop. The building is supplied with 480v delta. There is a 480v bus duct that runs along where the machine is going to be installed. Power supply line has to be large enough to handle 245 full load amps at 480v, 3 phase, 60 hertz. Main circuit breaker in control 300 amps.
A motor designed for 380V 50Hz, as commonly used in the EU, is therefore designed for a V/Hz ratio of 7.6:1. If you supply it with 480V (which is what a 460V motor is designed for), the ratio is 8:1, virtually the same. the motor will spin 20% faster because of the difference in frequency, but that can't be helped, you bought 50Hz equipment.
This is exactly what will happen in this case. It will run with following problems for a 50Hz motor running on 60Hz: The core loss will increase and cause over heating of core. As the core loss will increase, the Power Factor of motor will reduce. The motor speed will be higher, so shaft load will increase. Motor will be overloaded at rated load.
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can you run a 380v motor on 480v
